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5. An airplane must reach a velocity of 71 m/s for takeoff. If the runway is 1.0 km long, what
must the constant acceleration be?

Respuesta :

Answer:

final velocity 'v' = 71m/s distance 's' = 1000m intial velocity 'u' =0 therefore,using third equation of motion v^2- u^2=2*a*s 71*71=2*a*1000 a=71*71/(2*1000 a= 2.52m/s^2

Explanation:

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