Answer:
1, you would write it as x
Step-by-step explanation:
you use the equation [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
0 would be [tex]x_1[/tex]
1 would be [tex]y_1[/tex]
3 would be [tex]x_2[/tex]
and 4 would be [tex]y_2[/tex]
when you plug it into the equation, you get:
[tex]\frac{4-1}{3-0}[/tex]
when you solve, you get:
[tex]\frac{3}{3}[/tex]
then you simplify that and get 1, but when you write it into the equation you get x.
