Answer:
¹₀n+ ²³⁸₉₂U → ²³⁹₉₃Np + ⁰₋₁e
Explanation:
Key statement;
The first transuranium element neptunium, NpNp, was prepared by bombarding U−238U−238 with neutrons to form a neptunium atom and a beta particle.
This is the beta particle; ⁰₋₁e
¹₀n+ ²³⁸₉₂U → Np + ⁰₋₁e
The mass number of Np;
1 + 238 = Np + 0
Np = 239
The atomic number of Np;
0 + 92 = Np + (-1)
92 + 1 = Np
Np = 93
The equation is given as;
¹₀n+ ²³⁸₉₂U → ²³⁹₉₃Np + ⁰₋₁e
