A 33 % dextrous solution ( 33 mg per 100 mL of solution) is given intravenously. Suppose a total of 1.936 L of the solution is given over a n 11-hour period. Complete parts (a) through (c) below.

what is the flow rate in units of ml/hr?

mL/hr (Type an integer or decimal rounded to the nearest thousandth as needed.)

What is the flow rate in per hour?

nothing mg/hr (Type an integer or decimal rounded to the nearest thousandth as needed.)

b. If each mL contains 16 drops (the drop factor is expressed as 16 gtt/mL), what is the flow rate in units of gtt/hr?

nothing gtt/hr (Type an integer or decimal rounded to the nearest thousandth as needed.)

c. During the 11 -hour period, how much is delivered?

nothing mg (Type an integer or decimal rounded to the nearest thousandth as needed.)

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boffeemadrid boffeemadrid · Answer 1 · 2020-10-30T07:21:14+01:00

Answer:

[tex]176\ \text{ml/hr}[/tex]

[tex]58.08\ \text{mL/hr}[/tex]

[tex]11\ \text{gtt/hr}[/tex]

[tex]638.88\ \text{mg}[/tex]

Step-by-step explanation:

33 % dextrous solution ( 33 mg per 100 mL of solution)

1.936 L of the solution is given over an 11-hour period

So the flow rate in mL/hr is

[tex]\dfrac{1.936\times 10^3}{11}=176\ \text{ml/hr}[/tex]

The flow rate in ml/hr is [tex]176\ \text{ml/hr}[/tex]

Flow rate of dextrous in mL/hr is

[tex]0.33\times 176=58.08\ \text{mL/hr}[/tex]

The flow rate dextrous in mL/hr is [tex]58.08\ \text{mL/hr}[/tex]

Each mL contains 16 drops so flow rate in gtt/h is

[tex]\dfrac{176}{16}=11\ \text{gtt/hr}[/tex]

The flow rate in units of gtt/hr is [tex]11\ \text{gtt/hr}[/tex]

The mass of dextrous delivered 11 hours in mg is

[tex]0.33\times 1.936\times 10^3=638.88\ \text{mg}[/tex]

The mass of dextrous delivered 11 hours in mg is [tex]638.88\ \text{mg}[/tex]