Answer: The probability that: None will be defective = 0.8836
Step-by-step explanation:
Let x be the number of defectives watch.
As per given: p= 6%= 0.06 (probability of defective)
Sample size : n= 2
Binomial probability distribution formula : [tex]P(X=x)=^nC_xp^x(1-p)^{n-x}[/tex]
P(No defective)=P(X=0)
[tex]^{2}C_0(0.06)^0(1-0.06)^{2} =(1)(0.94)^2=0.8836[/tex]
Hence, The probability that: None will be defective = 0.8836
