Answer:
Step-by-step explanation:
I'll help you out
For #4:
4 Parallel means that the lines have the same slope, but different intercept
I'm going to assume it's 2y - 5x = 10
[tex]2y - 5x = 10\\2y = 5x + 10\\y = \frac{5x}{2}+5[/tex]
the slope is 5/2
We're given that it goes through the point (-10, 9),
we can substitute with the y = mx + b equation
[tex]y = mx + b\\9 = (-10)(5)/2 + b\\9 = -25 + b\\b = 34\\y = \frac{5}{2}x + 34[/tex]
5 Perpendicular means that the slope of the line is the negative reciprocal of the other line
The first line is y = 5, if you look at this on a graph, it's a straight horizontal line. it's slope is 0.
1/0 is undefined, it'd be a straight line upwards, which can be represented by x = (something)
we're given that it goes through (-2, 9)
so the line is
[tex]x = -2[/tex]
6
again, parallel = same slope
[tex]m = \frac{y_2-y_1}{x_2-x_1} \\m = \frac{8-3}{4-3}\\m = 5\\[/tex]
[tex]y = mx + b\\1 = 5(7) + b\\1 = 35 + b\\b = -34\\y = 5x - 34[/tex]
7
The two points are (0, 4) and (1, 7)
[tex]m = \frac{7-4}{1-0}\\ m = 3\\y = mx + b\\-3 = 3(5) + b\\-3 = 15 + b\\b = -18\\y = 3x - 18[/tex]
8
the two points are (0, -3) and (3, -1)
[tex]m_1 = \frac{-1 - (-3)}{3-0}\\ m_1 = 2/3\\m_2 = \frac{-3}{2} \\y = mx + b\\-2 = \frac{-3(2)}{2}+b\\ -2 = -3 + b\\b = 1\\y = \frac{-3}{2}x+1[/tex]
9
This is a straight up line, like in problem 5
it is x = -5
the perpendicular line is a horizontal line y = (something)
since it goes through 3 at -3, it is
[tex]y = 3[/tex]
10
the line is y = 4
a parallel line to this is another horizontal line y = (something)
since it goes through 8, the line is
[tex]y = 8[/tex]
