Answer:
Step-by-step explanation:
b)
[tex]\frac{2(x-5)}{3} + 4= 5x - 2\\\\\frac{2(x-5)}{3} + \frac{(3)(4)}{3} = 5x - 2\\\\\frac{2(x - 5) + 4(3)}{3} = 5x - 2\\\\2(x-5) + 4(3) = 3(5x - 2) --- multiplied- both -sides- by -3\\2(x) - 2(5) + 4(3) = 3(5x) - 3(2)\\\\2x - 10 + 12 = 15x - 6\\\\2x - 15x = -6 + 10 - 12\\\\-13x = -8\\\\x = \frac{8}{13}[/tex]
c)
[tex]3 - \frac{x + 2}{5} = 5(3x - 2)\\\\\frac{5(3)}{5} - \frac{x+2}{5} = 5(3x - 2)\\\\\frac{5(3) - (x + 2)}{5} = 5(3x - 2)}\\\\5 (3) - (x + 2) = 5(5)(3x - 2)\\\\15 - x - 2 = 25(3x - 2)\\\13 - x = 75x - 50\\\\75x + x = 13 + 50\\\\76x = 63\\\\x = \frac{63}{76}[/tex]
