contestada

A truck is traveling at an initial velocity
of +39m/s and it starts slowing down smoothly for 3.3s. It covers a distance of 45m while slowing down. What is the acceleration?​

Respuesta :

Answer:

Approximately [tex]-15.37m/s^2[/tex]

Explanation:

The acceleration can be found using the formula:

[tex]x_{f} = x_{i} + v_{i} (t)+\frac{1}{2} (a)(t^{2} )[/tex]

The work is as shown:

[tex]45m = 0 + 39 m/s (3.3s)+\frac{1}{2} a(3.3s)^2[/tex]

[tex]45m=128.7m + 5.445s^2 a[/tex]

[tex]-83.7m=5.445s^2a[/tex]

[tex]a = -15.37190083m/s^2[/tex]

a is about -15.37[tex]m/s^2[/tex]