Answer:
Four (4) IP fragments will be created by the router to forward this packet.
Explanation:
Datagram = 2700 bytes
IP Header = 20 bytes
Maximum Transmission Unit = 900 bytes
Original datagram is stamped with an identification number of 15
Required number of fragments = [tex]\frac{Datagram - IP header}{MTU - IP header}[/tex]
⇒ [tex]\frac{2700 - 20}{900 - 20}[/tex]
⇒ 2680 / 880 = 3.045
ceiling(3.045) = 4