Answer:
3.33 ml
Explanation:
We have
pH to be equal to pKa + log [ NaAc / HAc]
pH = 4.30
pKA = 4.78
This is expressed as
4.30 = 4.78 + log [ NaAc / HAc]
log [ NaAc / HAc] = - 0.48
[ NaAc / HAc] = 10^-0.48
= 0.33
Naac/HAc = 0.33
From here we cross multiply to get
NaAc = 0.33 HAc
The ratio can be given as 1 : 0.33 or 3:1
Moles of NaAc = 800 x 0.10 / 1000
= 0.08
With a ratio of 3 : 1 NaAC and HAc
We have 0.06 mol NaAc and 0.02 mol HAc
moles of HCl = 0.02 mol
Volume of Hcl = 0.02x1000 = 20
20/6.0
= 3.33 Ml
The volume of 6.0 M HCL should be 3.33 ml.
Since
pH to be equal to pKa + log [ NaAc / HAc]
pH = 4.30
pKA = 4.78
Now we can do like
4.30 = 4.78 + log [ NaAc / HAc]
log [ NaAc / HAc] = - 0.48
[ NaAc / HAc] = 10^-0.48
= 0.33
Naac/HAc = 0.33
Now
NaAc = 0.33 HAc
The ratio can be given as 1 : 0.33 or 3:1
So,
Moles of NaAc = 800 x 0.10 / 1000
= 0.08
With a ratio of 3 : 1 NaAC and HAc
We have 0.06 mol NaAc and 0.02 mol HAc
And,
moles of HCl = 0.02 mol
So,
Volume of Hcl = 0.02x1000 = 20
= 20/6.0
= 3.33 Ml
hence, The volume of 6.0 M HCL should be 3.33 ml.
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