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The speed of a 4.0-N hockey puck, sliding across a level ice surface, decreases at the rate of 2 m/s 2. The coefficient of kinetic friction between the puck and ice is:

Respuesta :

MrRoyal

Answer:

μ = 0.2041

Explanation:

Given

[tex]a = -2m/s^2[/tex]

Required

Determine the coefficient of friction (μ)

The acceleration is negative because it is decreasing.

Solving further, we have that:

[tex]F_f =[/tex] μmg

Where

μ = Coefficient of kinetic friction

[tex]F_f = ma[/tex]

So, we have:

ma = μmg

Divide both sides by m

a = μg

Substitute values for a and g

2 = μ * 9.8

Solve for μ

μ = 2/9.8

μ = 0.2041