Respuesta :
Answer:
Explanation:
The Electric field due to an infinite plane of positive charge with uniform surface charge density can be derived a s follows
let us assume An infinite positively charged sheet and lets take a cylindrical gaussian surface on this surface which is perpendicular to this plane of sheet
we know that positive charge electric field lines will be perpendicular to this sheet surface will be perpendicular to the cylindrical surface
applying gauss law
[tex]Electric field * Area =[/tex] [tex]charge/epsilon\\[/tex]
also sigma=Q/A ⇒ Q=sigma*A
so on one face
E*A=sigma*A/epsilon
also we notice this electric field on one face of the sheet is exactly equal to that on the another face hence electric field will be twice
2E*A=sigma*A/epsilon
final result
[tex]E= sigma/2*epsilon[/tex]
