Answer:
[tex]\dfrac{1}{64}[/tex] as loud.
Explanation:
The sound intensity varies inversely as the square of the distance from the sound source. Mathematically,
[tex]I=\dfrac{k}{d^2}[/tex]
You change your seat to one that is eight times as far from the speakers, d' = 8d.
New sound intensity is :
[tex]I'=\dfrac{k}{d'^2}\\\\I'=\dfrac{k}{(8d)^2}\\\\I'=\dfrac{1}{64}\times \dfrac{k}{d^2}\\\\I'=\dfrac{1}{64}\times I[/tex]
So, the new intensity is (1/64) times of the initial sound intensity.