Answer:
267.498 J is required to expand the volume of a pump from 0.0 L to 2.2 L against an external pressure of 1.2 atm
Explanation:
The volume change work of a gas is the work necessary for the gas to go from an initial volume Vi to a final volume Vf. If the volume decreases, the gas will have been compressed and it is a compression work; whereas if the volume increases, the gas will have expanded and it is expansion work.
The work is calculated by:
W= - P*ΔV= -P*(Vfinal - Vinitial)
In this case:
Replacing:
W= -121590 [tex]\frac{N}{m^{2} }[/tex]*0.0022 m³= - 267.498 N*m= -267.498 J
267.498 J is required to expand the volume of a pump from 0.0 L to 2.2 L against an external pressure of 1.2 atm
The work require to expand the volume of the given pump is 267.5 J.
The given parameters;
The work require to expand the volume of the given pump is calculated as follows;
W = PΔV
W = 1.2 atm (2.2 L - 0 L)
W = 2.64 atm.L
[tex]W = 2.64 \ atm.L \times \frac{101325 \ Pa}{1 \ atm} \times \frac{0.001 \ m^3}{1 \ L} \\\\W = 267.5 \ J[/tex]
Thus, the work require to expand the volume of the given pump is 267.5 J.
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