Answer:
(2, -3)
Step-by-step explanation:
[tex]f(x)=a(x-h)^2+k[/tex] vertex form of equation with vertex (h, k)
[tex]\left \big{f(x)=a(x-h)^2+k}\atop \big{f(x)=-(x-2)^2-3}\right\}\implies a=-1\,,\ h=2\,,\ k=-3[/tex]
So vertex of f(x) = - (x - 2)² - 3 is (2, -3)
