Answer:
y = - 10x + 1
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = [tex]\frac{1}{10}[/tex] x + 6 ← is in slope- intercept form
with slope m = [tex]\frac{1}{10}[/tex]
Given a line with slope m then the slope of a line perpendicular to it is
[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{\frac{1}{10} }[/tex] = - 10, thus
y = - 10x + c ← is the partial equation
To find c substitute (1, - 9 ) into the partial equation
- 9 = - 10 + c ⇒ c = - 9 + 10 = 1
y = - 10x + 1 ← equation of line q
