Respuesta :
First we need to calculate t(4) because x=4 for 4 shifts.
t(4) = 4*4 +3 = 19
Now because function "c" is declared as c(t(x)) for value x=4 we are searching c(19)! because t(4) = 19
c(19) = 2*19 + 5 = 43.
Answer is 43
t(4) = 4*4 +3 = 19
Now because function "c" is declared as c(t(x)) for value x=4 we are searching c(19)! because t(4) = 19
c(19) = 2*19 + 5 = 43.
Answer is 43
t ( x ) = 4 x + 3
c ( x ) = 2 x + 5
c ( t ( x ) ) = 2 * ( 4 x + 3 ) + 5 = 8 x + 6 + 5 = 8 x + 11
c ( 4 ) = 8 * 4 + 11 = 32 + 11 = 42
c ( x ) = 2 x + 5
c ( t ( x ) ) = 2 * ( 4 x + 3 ) + 5 = 8 x + 6 + 5 = 8 x + 11
c ( 4 ) = 8 * 4 + 11 = 32 + 11 = 42