Respuesta :
The 62nd term of the arithmetic sequence -27, -21, -15 is 339
Arithmetic sequence
The nth term of an arithmetic sequence is expressed as:
Tn =a+(n-1)d
Given the sequence -27, -21, -15
a is the first term = -27
d is the common difference = -21 + 27 = 6
n = 62
Substitute
T62 = -27 + (62-1)(6)
T62 = -27 + 61(6)
T62 = -27 + 366
T62 = 339
Hence the 62nd term of the arithmetic sequence -27, -21, -15 is 339
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