the perimeter of a triangle is 43 ft. The shortest side is one-third the length of the middle side. The longest side is 3 feet more than four times the shortest side. Find the lenghts of the three sides

Respuesta :

Answer:

shorter side = 5 feet, middle side = 15 feet, and longest side = 23 feet

Step-by-step explanation:

Given the perimeter of the triangle = 43 feet

Let the length of the middle side be represented by a. Then;

shortest side = [tex]\frac{1}{3}[/tex] x a

                     = [tex]\frac{a}{3}[/tex] feet

longest side = (4 x [tex]\frac{a}{3}[/tex]) + 3

                    = [tex]\frac{4a}{3}[/tex] + 3

Perimeter = a + [tex]\frac{a}{3}[/tex] + ([tex]\frac{4a}{3}[/tex] + 3)

⇒ 43 = a + [tex]\frac{a}{3}[/tex] + [tex]\frac{4a}{3}[/tex] + 3

43 - 3 = a + [tex]\frac{a}{3}[/tex] + [tex]\frac{4a}{3}[/tex]

40 = [tex]\frac{3a+a+4a}{3}[/tex]

    = [tex]\frac{8a}{3}[/tex]

40 x 3 = 8a

120 = 8a

a = [tex]\frac{120}{8}[/tex]

  = 15

Therefore,

middle side = 15 feet

shorter side = [tex]\frac{a}{3}[/tex] = [tex]\frac{15}{3}[/tex]

                    = 5 feet

longest side = (4 x [tex]\frac{a}{3}[/tex]) + 3

                    =  (4 x 5) + 3

                    = 23 feet