Answer:
[tex]d = 0[/tex]
Step-by-step explanation:
Given
[tex](6d+1)^2+12=13[/tex]
Required
Solve for d
[tex](6d+1)^2+12=13[/tex]
Collect Like Terms
[tex](6d+1)^2=13 - 12[/tex]
[tex](6d+1)^2=1[/tex]
Using square roots property
[tex]\sqrt{(6d+1)^2}=\sqrt 1[/tex]
[tex]6d+1 = 1[/tex]
Collect Like Terms
[tex]6d = 1 - 1[/tex]
[tex]6d = 0[/tex]
[tex]d = 0/6[/tex]
[tex]d = 0[/tex]