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A gas sample in a Boyle’s law apparatus is compressed to a volume of 22.0 mL. If its original volume was 37.0 mL at 12,000 Pa, what is the new pressure of the gas sample. Show your calculations.

Respuesta :

Stephen46

Answer:

The answer is 20,181 Pa

Explanation:

The new pressure can be found by using the formula for Boyle's law which is

[tex]P_1V_1 = P_2V_2[/tex]

Since we are finding the new pressure

[tex]P_2 = \frac{P_1V_1}{V_2} \\[/tex]

From the question we have

[tex]P_2 = \frac{37 \times 12000}{22} = \frac{444000}{22} \\ = 20181.81...[/tex]

We have the final answer as

20,181 Pa

Hope this helps you

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