Answer:
t₁ = 588 [N]
Explanation:
There are 2 forces acting in the free body diagram.
The weight of the beam w = 120*9,8
w = 1176 [N]
Force w= 1176 [N] ( the weight of the beam acting in the center of mass) and the tension t₁ in the vertical free end. As the system is in equilibrium, the sum of torque related to the attached point to the vertical wall must be equal to 0 then. Both forces are vertical forces therefore
∑T = f₁ * L/2 - t₁ * L = 0
1176*L/2 - t₁ * L = 0
1176/2 -t₁ = 0
t₁ = 588 [N]
