Answer:
-5.83 °C
Explanation:
Step 1: Given data
- Molality of the NaCl solution (m): 1.65 m
- Van't Hoff factor for NaCl (i): 1.9
- Freezing point depression constant (Kf): 1.86 °C/m
Step 2: Calculate the freezing point depression
The freezing point depression is a colligative property that can be calculated using the following expression.
ΔTf = i × m × Kf
ΔTf = 1.9 × 1.65 m × 1.86 °C/m
ΔTf = 5.83 °C
Step 3: Calculate the freezing point of the solution
The freezing point of pure water is 0°C. The freezing point of the solution is:
0 °C - 5.83°C = -5.83 °C
