Answer:
At [tex]20^oC[/tex] [tex]Z_{ppm} = 5263.15 \ ppm[/tex]
At [tex]50^oC[/tex] [tex]K_{ppm} = 30921 \ ppm[/tex]
Explanation:
From the question we are told that
The permissible exposure limit (PEL) for acetic anhydride is [tex]A =5 ppm[/tex]
The exposure that is of immediate danger to life and health [tex]B = 200 ppm[/tex]
Gnerally the vapor pressure of acetic anhydride at [tex]20^oC[/tex] is [tex]Z = 4.0\ mmHg[/tex]
Now converting to ppm from the description in the question
[tex]Z_{ppm} = \frac{4}{760 } * 10^{6} = 5263.15 \ ppm[/tex]
Gnerally the vapor pressure of acetic anhydride at [tex]50^oC[/tex] is [tex]K = 23.5 \ mmHg[/tex]
Now converting to ppm from the description in the question
[tex]K_{ppm} = \frac{23.5}{760 } * 10^{6} = 30921 \ ppm[/tex]
Note this vapor pressure are constant values
