Answer: [tex]9.28\times 10^{23}[/tex] atoms
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
General representation of an element is given as: [tex]_{Z}^{A}\textrm{X}[/tex]
[tex]_{35}^{79.90}\textrm{Br}[/tex]
where,
Z represents Atomic number
A represents Mass number
X represents the symbol of an element
1 mole of bromine [tex]Br[/tex] contains=[tex]6.022\times 10^{23}[/tex] atoms
1.54 moles of bromine [tex]Br[/tex] contains=[tex]\frac{6.022\times 10^{23}}{1}\times 1.54=9.28\times 10^{23}[/tex] atoms
Thus [tex]9.28\times 10^{23}[/tex] atoms are present in 1.54 moles of bromine.
