Answer:
558.42 g of Mn
Explanation:
Don't you forget the value of Avogadro's number: [tex]6.02x10^{23}[/tex]
The first thing you must do is a conversion factor using the following relationships:
1mol of Mn= 54.93g of Mn=6.02x10 to the 23 atoms of manganese.
The mass in grams of a mol of Mn can be obtained from your periodic table.
However the only part of this relationship required is:
54.93g Mn=6.02x10 to the 23 atoms of Mn
We start by multiplying the atoms of manganese by a the conversion factor:
[tex]6.12x10^{24} atoms Mn x\frac{54.93g Mn}{6.02x10^{23}atoms Mn }[/tex]= 558.42 g Mn
It means we multiply by 54.93 and divide by 6.02x10 to the 23.
In this case the unit atoms of Mn is canceled out and replaced by g of Mn, the desired unit. But it only happens when the positions of the numerator and denominator are correct. We can guarantee it by putting the given unit (in this case atoms of Mn) in the denominator. If we don't do this the units will never be canceled.
