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taskmasters
Given:
3n + 5

n = 1 ; 3(1) + 5 = 3 + 5 = 8
n = 2 ; 3(2) + 5 = 6 + 5 = 11
n = 3 ; 3(3) + 5 = 9 + 5 = 14
n = 4 ; 3(4) + 5 = 12 + 5 = 17

The first four terms of the sequence are: 8, 11, 14, 17.  Second option.

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Answer:

[tex]8,11,14,17[/tex]

Step-by-step explanation:

The rule for the given sequence is

[tex]a_n=3n+5[/tex]

To find the first term, we put [tex]n=1[/tex] into the formula to obtain;

[tex]a_1=3(1)+5[/tex]

[tex]a_1=3+5[/tex]

[tex]a_1=8[/tex]

To find the second term, we put [tex]n=2[/tex] into the formula to obtain;

[tex]a_2=3(2)+5[/tex]

[tex]a_2=6+5[/tex]

[tex]a_2=11[/tex]

To find the the third term, we put [tex]n=3[/tex] into the formula to obtain;

[tex]a_3=3(3)+5[/tex]

[tex]a_3=9+5[/tex]

[tex]a_3=14[/tex]

To find the first term, we put [tex]n=4[/tex] into the formula to obtain;

[tex]a_4=3(4)+5[/tex]

[tex]a_4=12+5[/tex]

[tex]a_4=17[/tex]

The first four terms of the sequence is

[tex]8,11,14,17[/tex]

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