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A normal force of 38 newtons acts on a book lying on a table. If the coefficient of static friction is 1.2, what is the minimum applied force required to slide the book?

Respuesta :

Edufirst
N = normal force = 38 newtons

Ks = coefficient of static friction = 1.2

Ff = maximum friction force = ks*N = 1.2 * 38 newtons = 45.6 newtons

F = minimum applied force = Ff

F = 45.6 newtons

Answer:

B,  46 newtons for Plato users

Explanation:

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