Answer:
[tex]M=1.62M[/tex]
Explanation:
Hello.
In this case, since the molarity is computed by the division of the moles of the solute by the volume of the solution in liters:
[tex]M=\frac{n_{solute}}{V_{solution}}[/tex]
We first compute the moles of glucose (molar mass 180 g/mol) as shown below:
[tex]n_{solute}=582.0g*\frac{1mol}{180g} =3.233mol[/tex]
Therefore, the molarity turns out:
[tex]M=\frac{3.233mol}{2.00L}\\ \\M=1.62M[/tex]
Best regards.
