What is the distance between (7,-2) and (3,1)

Answer:
Distance = 5
Step-by-step explanation:
x2 = 3
y2 = 1
x1 = 7
y1 = -2
=> d = Square root of (3 - 7)^2 + (1 + 2)^2
=> d = Square root of (-4)^2 + (3)^2
=> d = Square root of 16 + 9
= d = Square root of 25
d = 5