Answer:
79.29
Explanation:
Given that,
The y component of a vector, y = 36
The angle between the vector and the x-axis is 27.
We need to find the magnitude of a vector.
Let a and b are x and y component of a vector m. There resultant is R. So,
[tex]R=\sqrt{a^2+b^2}[/tex]
Where
[tex]a=c\cos\theta\ \text{and}\ b=c\sin\theta[/tex]
We have, b = 36 and θ = 27°
So,
[tex]36=R\sin\theta\\\\R=\dfrac{36}{\sin\theta}\\\\R=\dfrac{36}{\sin(27)}\\R=79.29[/tex]
So, the magnitude of the vector is 79.29
