A box contains 5 red balls, 3 green balls abd 4 blue balls. if two balls are drawn in succession without replacement, what is the propability that both are red?

Respuesta :

For the first red ball: 5/(5+3+4) = 5/12
For the second red ball 4/(4+3+4) = 4/11
(5/12) * (4/11) = 5/33

The probability that both are red is (5/12)(4/11) or 5/33 if the box contains 5 red balls, 3 green balls and 4 blue balls.

What is probability?

It is defined as the ratio of the number of favourable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.

We have a box contains 5 red balls, 3 green balls and 4 blue balls.

Total number of balls = 5+3+4 = 12

Number of red balls = 5

P(1st-getting red ball) = 5/12

P(2nd-getting red ball) = 4/11

The probability that both are red = (5/12)(4/11) or 20/132 or 5/33

Thus, the probability that both are red is (5/12)(4/11) or 5/33 if the box contains 5 red balls, 3 green balls and 4 blue balls.

Learn more about the probability here:

brainly.com/question/11234923

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