josh734853
josh734853
30-09-2020
Mathematics
contestada
x+3y−z=2
4x+2y+5z=1
3x+z=12
Respuesta :
mhanifa
mhanifa
30-09-2020
Answer:
x=5, y= -2, z= -3
Step-by-step explanation:
Given system of equations
x+3y−z=2 (1)
4x+2y+5z=1 (2)
3x+z=12 (3)
Solution
3*(2) - 2*(1)
10x + 17z = -1 (4)
17*(3) - (4)
51x - 10x + 17z - 17z = 12*17 - (-1)
41x = 205
x = 5
5*3 + z = 12 ⇒
z = -3
5 + 3y -(-3) = 2 ⇒ 3y = -6 ⇒
y = -2
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