Answer:
.36 M
Explanation:
2COF₂(g)⇌CO₂(g)+CF₄(g)
2 0 0
2 - 2a a a
a x a / (2 - 2a)² = 5
a² / 4 ( 1 -a )² = 5
a / ( 1 - a ) = √20
a / ( 1 - a ) = 4.47
a = 4.47 - 4.47 a
5.47 a = 4.47
a = .82
Concentration of COF₂ in equilibrium
= 2 - 2 a
= 2 - 2 x .82
= .36 M