Answer:
[tex]\frac{2x+7}{3}[/tex]
Step-by-step explanation:
Assuming you require a single fraction.
Given
[tex]\frac{2x+1}{3}[/tex] + 2 ← express 2 as [tex]\frac{6}{3}[/tex]
= [tex]\frac{2x+1}{3}[/tex] + [tex]\frac{6}{3}[/tex]
The fractions now have a common denominator, thus add the numerators leaving the denominator.
= [tex]\frac{2x+1+6}{3}[/tex]
= [tex]\frac{2x+7}{3}[/tex]
