moselouck
contestada

Hi, How would I go about solving this?
I got it wrong, so I must've missed something, I just don't know what.
My notes for rhombuses are: All sides are congruent. Diagonals are perpendicular. Diagonals are angle bisectors.

Hi How would I go about solving this I got it wrong so I mustve missed something I just dont know what My notes for rhombuses are All sides are congruent Diagon class=

Respuesta :

sqdancefan

Answer:

  ∠BAC = 122°

Step-by-step explanation:

From your notes, you know that ...

  ∠APB = 90°

  12y° = 90°

  y = 90/12 = 7.5

Then angle ACP is ...

  ∠ACP = (4y -1)° = (4(7.5) -1)° = 29°

Angle BAC is the ape.x angle of isosceles triangle BAC, whose base angles are 29°. Hence, ...

  ∠BAC = 180° -2(29°)

  ∠BAC = 122°

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