lindarrr
contestada

What is the percent error when a student measures the volume to be 19.3 liters when
the actual volume is 22.4 L.

Respuesta :

Answer:

The answer is

13.84 %

Explanation:

The percentage error of a certain measurement can be found by using the formula

[tex]P(\%) = \frac{error}{actual \: \: number} \times 100\% \\ [/tex]

From the question

actual volume = 22.4 L

error = 22.4 - 19.3 = 3.1

The percentage error is

[tex]P(\%) = \frac{3.1}{22.4} \times 100 \\ = 13.839285714...[/tex]

We have the final answer as

13.84 %

Hope this helps you