Using the normal distribution, it is found that the delivery time with a z-score of 1.2 is of 30.6 minutes.
The z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
In this problem, the mean and the standard deviation are given, respectively, by:
[tex]\mu = 27, \sigma = 3[/tex].
The delivery time with a z-score of 1.2 is X when Z = 1.2, hence:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]1.2 = \frac{X - 27}{3}[/tex]
X - 27 = 3 x 1.2
X = 30.6.
More can be learned about the normal distribution at https://brainly.com/question/24663213
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