Respuesta :

wegnerkolmp2741o

Answer:

see below

Step-by-step explanation:

(x) = 7 - 2x

Let t(x) =0

0 = 7-2x

Subtract 7 from each side

-7 = -2x

Divide by -2

-7/-2 =-2x/-2

7/2 =x

h(x) = 4x + 2

Replace x with x+3

h(x+3) = 4(x+3) + 2

Distribute

            = 4x+12 +2

            =4x+14

xKelvin

Answer:

19) [tex]x=\frac{7}{2}[/tex]

20) [tex]h(x+3)=4x+14[/tex]

Step-by-step explanation:

19)

We have the function:

[tex]t(x)=7-2x[/tex]

And we want to find x such that t(x)=0.

So, substitute 0 for t(x):

[tex]0=7-2x[/tex]

Solve for x. Subtract 7 from both sides:

[tex]-7=-2x[/tex]

Divide both sides by -2:

[tex]\frac{7}{2}=x[/tex]

Flip:

[tex]x=\frac{7}{2}[/tex]

20)

We have:

[tex]h(x)=4x+2[/tex]

To find h(x+3), substitute (x+3) for x. This yields:

[tex]h(x+3)=4(x+3)+2[/tex]

Multiply:

[tex]h(x+3)=4x+12+2[/tex]

Add:

[tex]h(x+3)=4x+14[/tex]

And we're done!

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