a driver brings a car to a full stop in 2.0 s. if the car was initially traveling at 22 m/s, what is the acceleration

Respuesta :

Answer: -11 m/s^2

Explanation: 22/2, it went to a full stop so it’s negative

The acceleration will be "-11 m/s²".

According to the question,

Time,

  • t = 2 s

Initially traveling,

  • [tex]V_0[/tex] = 22 m/s

Full stop means,

  • V = 0

As we know, the formula:

→ [tex]V = at +V_0[/tex]

By substituting the values, we get

→ [tex]0 = a\times t+V_0[/tex]

→ [tex]0 = a\times 2+22[/tex]

→ [tex]2a = -22[/tex]

→   [tex]a = -\frac{22}{2}[/tex]

→      [tex]= -11 \ m/s^2[/tex]

Thus the solution above is appropriate one.

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