8. Find the equation of a line in slope intercept form that is parallel to the line y = -2x - 3 that goes
through the point (2, 1).
Work:
Answer:

Find these 1st equation by using one point formula of point.
After this from equation 2 find slope, by comparing it with y= mx + c if it is in slope intercept form.
Then, as per the conditions of parallel lines, use m1=m2, then put the value of m1 in equation 1st.
Then simplify them.

So, let's work with these steps.

Now,

The equation of a st.line passing through point (2,1) is,

[tex](y - y1) = m1(x - x1)[/tex]

Put all values.

[tex](y - 1) = m1(x - 2)[/tex]

It is the 1st equation.

Another equation is,

y = -2x -3.......(ii)

Comparing the equation with y = mx+c.

Therefore, from equation (ii)

m2 = -2

Now, as per condition of parallel lines,

m1=m2= -2

Putting the value of m1 in equation 1st.

[tex](y - 1) = - 2(x - 2)[/tex]

y - 1 = -2x + 4

y = -2x +5.

Therefore, the equation is y = -2x +5.

Hope it helps...

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