rainazhongyangu rainazhongyangu

30-08-2020
Mathematics

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What is the smallest possible integer value of $x$ if $12\div(x+1)$ is an integer?

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PencilKnot PencilKnot

10-09-2020

Answer:

The answer is -13.

Step-by-step explanation:

We get the smallest value of [tex]x[/tex] when [tex]x+1[/tex] is the most negative factor of 12, which is -12. Therefore,

[tex]x+1=-12\\x=\boxed{-13}[/tex]

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