Answer:
[tex]\°C=5.8x10^3\°C[/tex]
[tex]\°F=1.1x10^4\°F[/tex]
Explanation:
Hello,
In this case, for the calculation of the temperature in degree Celsius we subtract 273.15 to the given temperature in kelvins:
[tex]\°C=6100-273.15\\\\\°C=5.8x10^3\°C[/tex]
Next, by applying the following equation we compute it in degree Fahrenheit:
[tex]\°F=(5.8x10^{3}*9/5) + 32\\\\\°F=1.1x10^4\°F[/tex]
Clearly, since the initial unit has two significant figures the computed units also show two significant figures.
Regards.
