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Consider the reaction below. If the concentration of B decreases by 0.068 M, what will be the change in concentration for C? 3A(g)+4B(g)⇋5C(g)

Respuesta :

Answer:

.085 M .

Explanation:

  3A(g)   +4B(g)  ⇋  5C(g)

4 moles of B reacts with A to form 5 moles of C

.068 moles of B will reacts with A to form  5 x .068 / 4 moles of C

Moles of C formed

= 5 x .068 / 4

= .085 moles .

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