Answer:
-15.5 kJ/mol
Explanation:
2A ⇄ 2B + C
[tex]$ K = \frac{[C][B]^2}{[A]^2} $[/tex]
= [tex]$ \frac{(0.69)(0.49)^2}{0.88^2} $[/tex]
= 0.21
T = [tex]$ 43.9^{\circ} $[/tex]C
= (273 + 43.9) K = 316.9 K
[tex]$ \Delta G^{\circ} = -19.4 $[/tex] kJ/mol
R = 8.314 J/k-mol = 0.008314 kJ/k-mol
[tex]$ \Delta G = \Delta G^{\circ} - RT \ln K $[/tex]
[tex]$ =-19.4 - 0.008314 \times 316.9 \ln (0.21) $[/tex]
= -15.5 kJ/ mol
