Answer:
The answer is
[tex]x \leq - \frac{8}{3} [/tex]
Step-by-step explanation:
[tex] - \frac{1}{4} x \leq - 8x - ( - 7x + 2)[/tex]
First expand the terms on the right side of the inequality
That's
[tex] - \frac{1}{4} x \leq - 8x + 7x - 2 \\ - \frac{1}{4} x \leq - x - 2[/tex]
Multiply through by 4
That's
[tex]4 \times - \frac{1}{4} x \leq - 4x - 8[/tex]
We have
[tex] - x \leq - 4x - 8[/tex]
Add 4x to both sides of the inequality
[tex] - x + 4x \leq4x - 4x - 8[/tex]
We have
[tex] 3x \le - 8[/tex]
Divide both sides by 3
We have the final answer as
[tex]x \leq - \frac{8}{3} [/tex]
Hope this helps you
