Explanation:
Wavelength of x-rays = 2 nm
Plane spacing, d = 0.281 nm
It is assumed to find the scattering angle for second order maxima.
For 2nd order, Bragg's law is given by :
[tex]2dsin\theta =n\lambda[/tex]
For second order, n = 2
[tex]sin\theta =\frac{n\lambda}{2d} \\Sin\theta =\frac{2\times2}{2\times0.281} \\\theta =\arcsin (7.14)[/tex]
Here, θ is not defined. Also, the wavelength of x-rays is more than the plane spacing. It means that it cannot produce any diffraction maximum.
