Answer:
The value is [tex]y'(t) = \frac{k}{\sqrt{y(t)} }[/tex]
Step-by-step explanation:
From the question we told that are
The rate of growth of mice is inversely proportional to the square of the population
This above statement can be mathematically represented as
[tex]\frac{d y }{dt} \ \ \ \alpha \ \ \frac{1}{\sqrt{y(t)} }[/tex]
Here [tex]y(t)[/tex] is the population
=> [tex]\frac{d y }{dt} = \frac{k}{\sqrt{y(t)} }[/tex]
=> [tex]y'(t) = \frac{k}{\sqrt{y(t)} }[/tex]
