Answer:
7 degree
Explanation:
given data
width = 4.1 inches
length = 35.4 inches
solution
we consider as per fig
O is mid point of BC
so OB = 2.05 inches
and
AB = [tex]\sqrt{OB^2 + OA^2}[/tex]
AB = [tex]\sqrt{2.05^2 + 35.4^2}[/tex]
AB = 35.078 inches
so
[tex]sin \frac{\alpha }{2} = \frac{OB}{AB}[/tex]
[tex]sin \frac{\alpha }{2} = \frac{2.05}{35.078}[/tex]
[tex]\alpha = 7 degree[/tex]
