Answer:
[tex]\mathbf{P (X \geq 2) = 1 - P( X \leq 1) \sum \limits ^1_{x=0} ( ^{1000}_x) (0.0035)^x (0.9965)^{1000-x}}[/tex]
Step-by-step explanation:
From the information given:
The probability that at least 2 crashes occurs in the next month can be estimated by using Poisson distribution because the sample size is large and the probability of the event p = 0.0035 is rare.
∴
Let X be the random variable that follows a Poisson distribution
The probability that at least 2 crashes occurs in the next month is:
[tex]\mathbf{P (X \geq 2) = 1 - P( X \leq 1) \sum \limits ^1_{x=0} ( ^{1000}_x) (0.0035)^x (0.9965)^{1000-x}}[/tex]
